2.What is the slope-intercept form of a line that contains the points (5, - 5) and has a slope of -3? 3. Write an equation of a line that is parallel to y = - 5/2 x + 3 but travels through the origin? (Note: Parallel lines have the same slope.)

2. y - (-5) = -3 (x - 5)

3. y = -5/2

Step-by-step explanation:

Point intercept form: y - y₁ = m (x - x₁)

Where y and x are just kept as y and x, y₁ and x₁ are the parts of a coordinate, and m = slope.

2. The points are (5, -5) and the slope is -3. Plug this into y - y₁ = m (x - x₁) to get

y - (-5) = -3 (x - 5)

3. As stated, parallel lines have the same slope, so the slope of the line would be -5/2. The origin is (0, 0), so plug these two numbers in.

y - y₁ = m (x - x₁)

y - 0 = -5/2 (x - 0)

y = -5/2

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

you can not solvr this without numbers