What is the equation of the line with a slope of 2 through (-4, 6) in point-slope form? O y = 2x + 14
Oy-6 = 2 (x +4)
Oy= 2x – 14
Oy+6 = 2 (x – 4)

y - 6 = 2(x + 4)

Step-by-step explanation:

Point slope form is y - = m (x - ).

and are the points that they give you in the problem, which is (-4, 6), and m is the slope, which is 2.

When you plug everything in, you should get

y - 6 = 2(x + 4).

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.