3 dimes 2 pennies 4 nickels and 2 quarters what's the probability that all three coins are nickels

i think it will be 40 percent not sure

There are numerous ways of combining the coins to get 25 cents and more. You will end up doing a lot of combinations that might get you confused. What we can do is to find the combination that gives us coins less than 25 cents and subtract it from the total combination for selecting any three (3) coins.

Total for selecting any three coins = 9C3 = 84

Selection of coins that give us less than 25 cents ( (1 dime,2 nickels, & 0 quarters) or ( 0 dime, 3 nickels & 0 quarters)

                              = 4C1*3C2*2C0  + 4C0*3C3*2C0

                                         = 4(3)(1) + 1(1)(1) = 13

Therefore the selection of coins that gives us at least 25cents = 84 -13 =71

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b