Jackie wrote the number 238,741 on the board. In which number is the value of the digit 7 exactly 10 times the value of the digit 7 in the number Jackie wrote?

x = 7000 OR 7360 OR 237,410 OR 270,00 etc.

Step-by-step explanation:

Given - Jackie wrote the number 238,741 on the board.

To find - In which number is the value of the digit 7 exactly 10 times the

              value of the digit 7 in the number Jackie wrote?

Proof -

given that the number Jackie wrote = 238, 741

The value of digit 7 = 100 (Hundred's place)

Now,

Let the number = x in which the value of 7 is exactly 10 times the value of the digit 7 in the number Jackie wrote.

Now,

The value of digit 7 in x = 10 × value of digit 7 in Jackie number

                                       = 10 × 100

                                       = 1000

⇒The value of digit 7 in x = 1000 ( Thousand's place)

So, The number can be

x = 7000

Or

x = 7360

OR

x = 237,410

OR

x = 270,00 etc

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0