A square on a coordinate plane has one vertex at ​(3.5​,2​) and a perimeter of 18 units. If all of the vertices are located in Quadrant​ I, what are the coordinates of the other 3​ vertices?

Vertex 2 =  (3.5, 6.5)

Vertex 3 = (8, 2)

Vertex 4 = (8, 6.5)

Step-by-step explanation:

Given that:

Perimeter, P = 18 units

Perimeter of a square = 4s ; s = side length

18 = 4s

s = 18/4

s = 4.5 units

If Vertex 1 = (3.5, 2) and all vertexes are located in quadrant 1

Vertex 2 = (3.5, 2+4.5) = (3.5, 6.5)

Vertex 3 = (3.5+4.5, 2) = (8, 2)

Vertex 4 = (8, 2+4.5) = (8, 6.5)

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.

it is 570

step-by-step explanation: