Teachers at Green High School have asked students which social media site they prefer. Students in two classes have been surveyed. The following question has three parts. First, answer Part A Second, answer Part B. Then, answer Part C Mr. Smith asked his classif
they used either Social Media A Social Media B. both, or neither. He compiled the results in a Venn diagram
Co.
Parta
Use the Venn diagram to select the correct answers to complete the sentences
Find AUB-
students
These are students that
Find an Be
students

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step-by-step explanation:

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linear pair postulates

step-by-step explanation: 4 cause 2+2=4

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.