Ms. Abreau is flying to Florida for the 90° Angle Conference, where the temperature s just right. Her plane is 1200 feet in the air and the runway is 3400 feet horizontally away. What is the angle of depression formed from the plane to the runway ? Round to the nearest tenth if necessary and just the number please in your answer, we know it is degrees.

19.4 degrees

Step-by-step explanation:

Using the SOH CAH TOA trigonometry identity

Given

Height of plane from the ground= 1200 = adjacent

Horizontal distance = 3400ft = Adjacent

Required

angle of depression theta

tan theta = opp/adj

tan theta = 1200/3400

tan theta = 12/34

tan theta = 0= arccos.3529

theta=  (0.3529)

theta = 19.4 degree

Hence the angle of depression is 19.4 degrees

i pretty sure it is

898.1666667

step-by-step explanation:

5389/6 = 898.1666667