A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible width

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)        

Given L = W + 2      and the perimeter is greater than 112 meters?

  P rect    <   2(L +W)        L = W + 2

  P rect    <   2(W + 2 +W)

                <   2(2W+2)

  112         <     4W + 4        solve for W

(112 - 4)/4  <   (4W +4 - 4)/4              

108/4       <   (4W + 0)/4

       27     <    W              

      the width has to be greater than 27 meters

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.