A professor holds office hours during final exam week and discovers much to his dismay that his sudden popularity affords him little time to engage in his favorite activity, watching cat videos. Fifteen students per hour arrive at his office and he patiently answers questions, averaging three minutes per student. On average, how many students are waiting to ask questions?

There are no student waiting to ask questions

Step-by-step explanation:

The number of students that arre

The arrival rate of the student, λ = 15/hr

The number of minutes spent per student, W = 3 minutes

The number of students waiting to ask questions, 'L', is given by Little's law as follows;

L = λ·W

Where;

L = The number of students in the system

λ = The arrival rate = 15 students/hour

W = The average time spent in the system = 3 minutes = 1/20 hour

∴ L = 15 student/hour × (1/20) hour = 3/4 Students

Given that the number of students waiting to ask questions is a fraction, less than 1, we round down, and there are therefore no student waiting to ask questions

ce pula mea vrei ma

step-by-step explanation:

gayule

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.