Fine two integers that have a sum of -17 and a product of 52. What are the integers?

-4 x -13 are the two integers that have a product of 52 and a sum of -17!

Have a great day/night! ^^

{4, 13}

Step-by-step explanation:

Represent the integers by I and J.  Then I + J = -17 and I*J = 52.

Let's solve this system using substitution.  Solve the first equation for I as follows:  

I + J = -17 becomes I = -J - 17

Substitute -J -17 for   I   in the second equation:

(-J - 17)*J = 52

Performing the indicated multiplication, we get:

-J^2 - 17J - 52 = 0

Let's solve this using the quadratic formula.  The quadratic coefficients here are {-1, -17, -52}, and so the discriminant, b^2 - 4ac, is

(-17)^2 - 4(-1)(-52), or 289 - 208, or 81.  This result is positive, so we know that the quadratic equation has two real, unequal roots.  They are:

      17 ± √81         17 ± 9

J =   =

         2(-1)                  -2

Evaluating this last result, we get J = (17 + 9)/2, or J = 13, and

J = (17 - 9)/2 = 8/2, or J = 4

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

ver más en -

step-by-step explanation: