Enter an expression equivalent to (3x^2+2y^2-3x)+(2x^2+y^2-2x)-(x^2+3 y^2+x) using the fewest number of possible terms

2x(2x - 3)

Step-by-step explanation:

Given:

(3x^2+2y^2-3x)+(2x^2+y^2-2x)-(x^2+3y^2+x)

Written as:

(3x² + 2y² - 3x) + (2x² + y² - 2x) - (x² + 3y² + x)

= 3x² + 2y² - 3x + 2x² + y² - 2x - x² - 3y² - x

Collect like terms

= 3x² + 2x² - x² + 2y² + y²- 3y² - 3x - 2x - x

= 4x² + 0 - 6x

= 4x² - 6x

= 2x(2x - 3)

stop using this to cheat on home work

step-by-step explanation:

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your answer is a

step-by-step explanation:

4*4*4*4=256