Plz help will give what I got (45 points) 4. Find the standard form equation of the quadratic function that has a vertex at (2, 5) and goes through the point (3, 8). Show your work. (6 points total)
Step 1: Substitute the vertex into y = a(x – h)2 + k. (1 point)

Step 2: Substitute (3, 8) into the equation and solve for a. (2 points)

Step 3: Substitute the value of a back into the vertex form. (1 point)

Step 4: Expand the binomial and use the distributive property to rewrite the vertex form in standard form. (2 points)

ok i think i can answer

Step-by-step explanation:

did a picture come with this tho?

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: