Plz help will give what I got (74 points) 4. Find the standard form equation of the quadratic function that has a vertex at (2, 5) and goes through the point (3, 8). Show your work. (6 points total)
Step 1: Substitute the vertex into y = a(x – h)2 + k. (1 point)

Step 2: Substitute (3, 8) into the equation and solve for a. (2 points)

Step 3: Substitute the value of a back into the vertex form. (1 point)

Step 4: Expand the binomial and use the distributive property to rewrite the vertex form in standard form. (2 points)

When written in "vertex form":

• (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.

• the h represents a horizontal shift (how far left, or right, the graph has shifted from x = 0).

• the k represents a vertical shift (how far up, or down, the graph has shifted from y = 0).

• notice that the h value is subtracted in this form, and that the k value is added.

            If the equation is y = 2(x - 1)2 + 5, the value of h is 1, and k is 5.

            If the equation is y = 3(x + 4)2 - 6, the value of h is -4, and k is -6.

Step-by-step explanation:

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.