Find the slope of the line that passes through (6, 3) and (10, 6)

Step-by-step explanation:

3/4

insert 1st point into y=mx+b

3=m(6)+b

insert 2nd point into y=mx+b

6=m(10)+b

use system of equations to solve for m and b

b=3-6m

b=6-10m

3-6m=6-10m

4m=3

m=3/4

insert back into the equation

3=(3/4)6+b

3=9/2+b

3-9/2=b

-3/2=b

insert back into y=mx+b

m=slope

b=y-intercept

y=(3/4)x-3/2

slope=3/4

Hope that helps :)

u dumb boi

step-by-step explanation: