First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below:
![\sqrt{\frac{ {72x}^{16} }{ {50x}^{{{36} }}}} = \frac{ { \sqrt{72}x}^{ {16}^{ (\frac{1}{2}) } } }{ { \sqrt{50} x}^ {{36}^{ (\frac{1}{2}) } }}](/tex.php?f= \sqrt{\frac{ {72x}^{16} }{ {50x}^{{{36} }}}} = \frac{ { \sqrt{72}x}^{ {16}^{ (\frac{1}{2}) } } }{ { \sqrt{50} x}^ {{36}^{ (\frac{1}{2}) } }})
multiply exponents per exponent rules to get:
![\frac{ { \sqrt{72}x}^{8} }{ { \sqrt{50}x}^{18} }](/tex.php?f= \frac{ { \sqrt{72}x}^{8} }{ { \sqrt{50}x}^{18} } )
remember you subtract exponents from the denominator and add exponents in the numerator so:
![\sqrt{ \frac{72}{ 50}} \times ( {x}^{(8 - 18) } ) = \sqrt{ \frac{36}{25} } \times ( {x}^{ - 10} )](/tex.php?f= \sqrt{ \frac{72}{ 50}} \times ( {x}^{(8 - 18) } ) = \sqrt{ \frac{36}{25} } \times ( {x}^{ - 10} ))
simplify further:
![\frac{6}{5} {x}^{ - 10} = \frac{6}{5 {x}^{10} }](/tex.php?f= \frac{6}{5} {x}^{ - 10} = \frac{6}{5 {x}^{10} } )
so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.
![Plz hurrywhat is the simplified form of ? assume x ≠ 0.](/tpl/images/02/05/qlOnC5YEEDocj5fo.jpg)