Points! + whoever answers both correctly gets to be the

57x^5 (divided by) 19x^2

part b. determine the excluded value(s) of the variable. in two or more complete sentence, explain how you determine the excluded value and why it cannot be possible value for the variable.

First off the answer to the problem is 3x^7 Multiply 3 3 by −7 - 7 to get −21 - 21 . Move all terms containing x x to the left side of the equation. Since 3x 3 ⁢ x contains the variable to solve for, move it to the left side of the equation by subtracting 3x 3 ⁢ x from both sides. Subtract 3x 3 ⁢ x from 3x 3 ⁢ xto get 0 0
hope it helped =)

(ab)/(cd)=(a/c)(b/d)
and
(x^m)/(x^n)=x^(m-n)

so
(57x^5)/(19x^2)=(57/19)(x^5/x^2)=(3)(x^5-2)=3x^3

excluded values are the factors factored out

57/19=(19*3)/(19)
excluded value is 19

for
(x^5)/(x^2)=(x^2*x^3)/(x^2)
excluded value is x^3

so

excluded values are 19 and x^3

(6,0) i hope it makes enough sense