HELP Question 3 (1 point)

What is the domain of the function f(x)=2x+3

?
Question 3 options:

x>0

x>3

x>−3

All real numbers
Question 4 (1 point)

What is the range of the functionf(x)=2x+3

?
Question 4 options:

y>0

y>3

y>−3

All real numbers
Question 5 (1 point)

What is the end behavior of the functionf(x)=2x+3

?
Question 5 options:

As x→−∞, y→∞
and x→∞, y→3

.

As x→−∞, y→−∞
and x→∞, y→−3

Asx→−∞, y→3
and x→∞, y→∞

.

Asx→−∞, y→−3
and x→∞, y→−∞.

3) All real numbers

4) y > 3

5) C) the only choice that ends with a POSITIVE ∞

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!