Log2 (X^2+3x+2)=1 state the universe and solve each of the following for x.​

By "state the universe" I suppose you mean "domain". log₂(x ² + 3x + 2) is defined for

x ² + 3x + 2 = (x + 1) (x + 2) > 0   →   x < -2   or   x > -1

(To solve the inequality, consider values of x between the ones that make the expression exactly equal to 0, in this case x = -2 and x = -1. We have, for instance, for x = -3, that (-3)² + 3(-3) + 2 = 2 > 0, so x ² + 3x + 2 > 0 for all x < -2.)

Now solve the equation: Write both sides as powers of 2 to eliminate the logarithm on the left:

Solve the remaining quadratic:

x ² + 3x + 2 = 2

x ² + 3x = 0

x (x + 3) = 0

x = 0   or   x = -3

Both of these solutions are within the presribed domain (-3 < -2 and 0 > -1), so we're done.

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6

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step-by-step explanation: