A ball is thrown into the air. The height h, in feet, of the ball after x seconds is given by the function h = −16(x − 2)2 + 72. What is the equation in standard form and the maximum height of the ball? A. h(x) = −16x2 + 32x + 72; 72 ft
B. h(x) = −16x2 − 32x + 72; 32 ft
C. h(x) = −16x2 − 64x + 32; 32 ft
D. h(x) = −16x2 + 64x + 8; 72 ft

Step-by-step explanation:

h = −16(x − 2)² + 72

 =  −16((x − 2)(x − 2)) + 72                   expand the square  (x - 2)² =  (x - 2)(x - x)

 =  -16 ((x)(x) + (x)(-2) + (-2)(x) + (-2)(-2)) + 72

  = -16 (x² + (-2x) + (-2x) + (4) ) + 72

  = -16 (x² + (-4x)  + (4) ) + 72

  = -16 (x² - 4x  + 4 ) + 72

  = (-16)(x²) + (-16)(-4x) +(-16)(4) + 72

  =   -16x²  + 64x  - 64 + 72

  =   -16x²  + 64x  + 8              My guess is D   ; 72 ???

I have no clue what the  ; 72 means after the given answer.  It must be a standard form thing I never learned.

A. -16x²+64x+8

B. 72 ft.

Step-by-step explanation: A. Expand the perfect square binomial -16(x²-4x+4)+72, dist. -16 (-16x²+64x-64+72), then combine like terms (-16x²+64x+8)

B. Find the abs. max. by looking back at the vertex form. The max is (2,72). Use the y-value for the height.

Have a great day : )

ik how do do this just give me a few minutes and i will give it to

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.