At the beginning of the road, a tank truck was traveling full of water in the water tank, but it began to leak. You can assume
that the fuel consumption of the truck is directly proportional to the weight it carries, and that the water flow in the leakage) and the speed of the truck are constant for the whole journey. After traveling for miles, the truck leaked half of the water from the water tank and consumed half of the fuel tank. If the water tank was empty, the truck would have spent a
sixth of the fuel tank, if it travelled the same distance and under the same conditions as above. Disregarding the fuel tank weight, what fraction of the fuel tank would be spent by the truck if there was no leak?

10 you would take 50/ .2

step-by-step explanation:

360/29

step-by-step explanation:

answer: 193

explanation:

200-7 = 193

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v