Solve the equation on the interval [0,2pi]:
(2cosx+1)(2sinx+√3)=0...
Mathematics, 18.03.2021 04:20 aleilyg2005
Solve the equation on the interval [0,2pi]:
(2cosx+1)(2sinx+√3)=0
Answers: 3
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Either enter an exact answer in terms of \piπ or use 3.143.14 for \piπ and enter your answer as a decimal.
Answers: 2
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