The width of a rectangle is 4cm less than the length. If each dimension were increased by 3cm, the width of the new rectangle formed would be 2/3 the length of the new rectangle. Find the dimensions of the original rectangle.

The original length is 9 cm and the original width 5 cm

Step-by-step explanation:

The area of  a rectangle A is given as the product of its' length L and width W.

Given that the width of a rectangle is 4cm less than the length then

W = L - 4

If each dimension were increased by 3cm, then the new

Length

= L + 3

Width

= W + 3

the width of the new rectangle formed would be 2/3 the length of the new rectangle

W + 3 = 2/3(L + 3)

3W + 9 = 2L + 6

3W = 2L +6 - 9

3W = 2L - 3

Recall that W = L - 4

3(L - 4) = 2L - 3

3L - 12 = 2L - 3

3L - 2L = 12 - 3

L = 9 cm

W = 9 - 4

= 5 cm

x=12 units bd= 10 units

step-by-step explanation:

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5