Does the line passing through the points (3, 3) and (7, 11) intersect the line passing through the points (5, 8) and (13, 24

I understand why you are asking about this Ammaria, these type of questions take a lot of understanding of graphing.  Please feel ok asking me questions :)

Step-by-step explanation:

we are given two points

P1 = (3,3)  in the form (x1,y1)

P2 = (7,11) in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

m = (11-3) / (7-3)

m = 8 / 4

m = 2

now use the slope along with one of the given points, either one will work, i'll use P1 , and put that into the point-slope formula.

y-3 = 2(x-3)

y -3 = 2x -6

y = 2x -3

So with the above formula we can check to see if the points work by plugging them into the formula.  

P3 = (5,8)

8 = 2(5) - 3

no point 3 does not work so it's not on the line

P4 = (13, 24)

24 = 2(13) - 3

no point 4 does not work either.

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.