Is it possible for a reasonable system of linear equations in three variables to have a unreasonable solution? Provide your reasoning.

Yes. There could be no solution to a reasonable system, which is unreasonable.

No. There are no unreasonable solutions.

Yes. When equations are modeled after real-world situations, they don't always result in
solutions that can be applied to the given situation, or may result in values that just don't
make sense.

No. The solution is always technically accurate. So if the solution is unreasonable, then the
entire system must be unreasonable

Yes. When equations are modeled after real-world situations, they don't always result in

solutions that can be applied to the given situation, or may result in values that just don't

make sense.

Step-by-step explanation:

An unreasonable solution could be, for example, you want to make $1M in sales of your new rap song. If you sell 1 a day for .99 cents. How long will it take to make $1m? It would take 1,010,101 days or 2,767 + years. You may be living large—but you won’t live to see 2,767 birthdays so this is a solution, but an unreasonable one

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

step-by-step explanation:

most likely the answer is a.

alice wins if a total of 5 is rolled. finn wins if a total of 9 is rolled.