In a class, there are twice more boys than girls. Six boys leave the class and six girls arrive ; therefore, there are twice more girls than boys .
How many boys and girls were there at first ?
please show calculations steps plus this should be solved as a system​

Boys= 12

Girls= 6

Step-by-step explanation:

Let no: of girls be 'x'

No: of boys= 2x

boys after= 2x-6

girls after = x+6

according to the question,

2(2x-6)=x+6

4x-12=x+6

3x=18

x=6

No: of girls at first= 6

No: of boys at first=2*6=12

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180