The admission fee at an amusement park is $2.25 for children and $5.40 for adults on a certain day 271 people enter the park and the admission fees collected a total of $972 how many children and how many adults were admitted?

115 adults and 156 children were admitted at the amusement park.

Step-by-step explanation:

Given that the admission fee at an amusement park is $ 2.25 for children and $ 5.40 for adults, and on a certain day 271 people enter the park and the admission fees collected a total of $ 972, to determine how many children and how many adults were admitted se you must perform the following calculation:

5.40 - 2.25 = 3.15

271 x 2.25 = 609.75

(972 - 609.75) / 3.15 = X

362.25 / 3.15 = X

115 = X

(115 x 5.40) + ((271-115) x 2.25) = X

621 + (156 x 2.25) = X

621 + 351 = X

972 = X

Thus, 115 adults and 156 children were admitted at the amusement park.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47