Which expression represents the ratio of the difference of the two means to Sidney's mean absolute deviation

The ratio of the difference of the two means to Sidney's mean absolute deviation = = 1.2195

Step-by-step explanation:

P.S - The exact question is -

Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.

                                       Sidney’s Grades           Phil’s Grades

Mean                                     82                                    78

Mean Absolute Deviation      3.28                                 3.96

To find - Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?

Proof -

Given that Mean of Sidney Grades = 82

                 Mean of Phil's   Grades = 78

So,

The difference of two means = 82 - 78 = 4

Also,

Given, Mean Absolute Deviation of Sydney = 3.28

Now,

The ratio of the difference of the two means to Sidney's mean absolute deviation = = 1.2195

answer:

c 60% on edg

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: