One side of a square was reduced by 3 in and the other side was enlarged by 11 inches. The area of a resulting rectangle is 15 inches squared.
Find the side of the square.

Each side of the square is 4 inches long

Step-by-step explanation:

Original side: x

(x-3)*(x+11)=15

x^2 + 8x - 48 = 0

If you solve the equation your answer would by x=4 inches.

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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