A 13-foot long ladder is placed against a wall and then the base of the ladder is pulled away from the wall. As the base of the ladder is pulled away from the wall, the top of the ladder slides down the wall (and the length of the ladder stays fixed). Let x represent the distance (in feet) from the base of the ladder to the wall, and let θ represent the radian measure of the angle the ladder forms with the ground.

Suppose the base of the ladder is 9 feet from the wall (x=9). What is the value of θ?
θ=

Write a formula that expresses θ in terms of x.
θ=

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Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )