The length of a rectangle is twice as long as the width. The area is 200ft to the power of 2. Find the length and the width of the rectangle.

Length = 20feet

Width = 10feet

Step-by-step explanation:

Area of a rectangle = LW

Perimeter P= 2(L+W)

L is the length

W is the width

If the length of a rectangle is twice as long as the width, then;

L = 2W

Substitute into the foemula

A  = (2W)W

A=  2W²  

If the area is 200ft², then;

200 = 2W²

100 = W²

W = √100

W = 10ft

Since L = 2W

L = 2(10)

L = 20ft

Hence the length of the rectangle is 20feet and the Width is 10feet

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629