GIVNING BRAINLIST Quadratic functions “q” and “w” are graphed on the same coordinate grid the vertex of the graph of “q” is 11 units below the vertex of the graph of “w”. Which pair of functions could have been used to create the graphs of “q” and “w”

A. Q(x) = 11 and w(x) =
B. Q(x) = + 11 and w(x) =
C. Q(x) = -11 and w(x) =
D. Q(x) = -11 and w(x) =

I think it might be C

Step-by-step explanation:

I think C. please give other person brainliest though

Step-by-step explanation:

47 - 90 = 43

43 - 180 = x

x = 137

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .