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Mathematics, 18.03.2021 02:10 sskibi1243

The work of a student trying to solve the equation 4(2x βˆ’ 1) = 11 + 3x + 5 is shown below: Step 1: 4(2x βˆ’ 1) = 11 + 3x + 5
Step 2: 8x βˆ’ 4 = 16 + 3x
Step 3: 8x + 3x = 16 βˆ’ 4
Step 4: 11x = 24
Step 5: x = 2.18

In which step did the student first make an error and what is the correct step?

Step 2: 8x βˆ’ 1 = 16 + 3x
Step 2: 8x βˆ’ 8 = 6 + 3x
Step 3: 8x βˆ’ 3x = 16 + 4
Step 3: 8x + 3x = 16 βˆ’ 8

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The work of a student trying to solve the equation 4(2x βˆ’ 1) = 11 + 3x + 5 is shown below: Step 1:...
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