A vertical parabolic sag curve has a grade of -0.4% followed by a grade of 2% intersecting at station 12 150.60 at elevation 124.80 m above sea level. The change of grade of the sag curve is restricted to 0.6%. (a) Compute the length of the curve (b) Compute the elevation of the lowest point of the curve (c) Compute the elevation at Sta. 12 125.60

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

cutt.ly/4zZs6GM

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

c

step-by-step explanation:

c