An automobile dealer can sell 12 cars per day at a price of $17,000. He estimates that for each $300 price reduction he can sell two more cars per day. If each car costs him $14,000, and fixed costs are $1000, what price should he charge to
maximize his profit? [Hint: Let x = the number of $300 price reductions.]
How many cars will he sell at this price?

$ 1100

Step-by-step explanation:

Let p(x) be the price he charges for a car after x price reductions.

Since car costs him $10,000, and fixed costs are $1000

p(x) = 13000-10000-1000-300x = 2000 - 300x

Let  q(x) = 12 + 2x the quantity of cars sold after x price reductions.

and the profit he can make are given by:

Profit = R(x) = (12+2x)(13,000 - 10,000 - 1,000 - 300x) dollars.

As you can see, maximizing profit , we have to check where P'(x) = 0

And P''(x)<0.

So we get x = 3.

Replacing the value we get we get 2000 - 300 X 3 = 2000 - 900

                                                                 = $ 1100

]

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation:

answer: answer is b.

[m < b = 120º]

step-by-step explanation: