Find the 12" term of the arithmetic sequence whose common difference is d=8 and whose first term is a = -2. Can someone please help me?

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86.

Step-by-step explanation:

nth term = a1 + d(n - 1) so here we have:

12the term = -2 + 8( 12 - 1)

= -2 + 88

= 86.

i got 86 for this

hope this !

if you need an explanation just ask

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3