Mathematics, 18.03.2021 01:00 Jony4359
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A ball is thrown straight up from the top of a building 144 ft tall with an initial velocity of 48 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 144 + 48t − 16t^2.
Find the maximum height attained by the ball.
Answers: 2
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Grant simplified the expression 1.5(-3.2 + 2.5) his work is shown below explain the error in grants work
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PLEASE HELP ASAP
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