The discriminant of a quadratic equation is the value b^2-4ac what is the value of discriminant of 0=-2x^2+6x+13

-16

Step-by-step explanation:

Given data

We are given the expression

0=-2x^2+6x+13

a=-1

b=6

c=13

The discriminant of a quadratic equation is the value b^2-4ac

Substitute

=6^2-4(-1*13)

=36-4(13)

=36-52

=-16

Hence the discriminant is -16

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)

5: 20

step-by-step explanation: