How do I solve this equation by using the quadratic formula 3x^2-12x-27=-6

Move all terms to the left side of the equation and simplify.

3x²−12x−21=0

Use the quadratic formula to find the solutions.

(−b±√b²−4(ac))/2a

Substitute the values a=3, b=−12, and c=−21 into the quadratic formula and solve for x.

(12±√(−12)²−4⋅(3⋅−21)0/2⋅3 Simplify =>  x=2±√11

The result can be shown in multiple forms.

Exact Form: x=2±√11

Decimal Form: x=5.31662479…,−1.31662479…

Step-by-step explanation:

Step-by-step explanation:

The quadratic equation is

x=−b=−√b2−4ac2a

for a quadratic taking the form

ax2+bx+c=0

So for this equation it is

x=−(−12)±√(−12)2−4⋅3⋅112⋅3

x=12±√144−1326

x=12±√4⋅36

x=6±√33

the answer is (-4,-4)

hope this ! : d

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5