A ranch hand herded his cattle to some grazing land. Then he began riding back to the ranch, which is due west, at 7 miles per hour. Simultaneously, the cows began moving away from
him, too, headed due east at 3 miles per hour. How long did it take for the herd and the
ranch hand to be 2 miles apart? (Please help me !!)

1/5 hr or 12 min

Step-by-step explanation:

We are going to use the formula D = RT

Let t = the time for  them to be 2 mi. apart

Then 7t = the distance the ranch hand traveled

and 3t = the distance the cows traveled

Since they traveled in opposite directions, the sum of their distances will give us how far they are apart.

So, 7t + 3t = 2

10t = 2

t = 2/10 = 1/5 hr. =  12 min.

.19875994384

step-by-step explanation:

1699/ 8548

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.