What are all of the zeros in this equation?

0, 1 and 1

Step-by-step explanation:

Given the expressions;

x^3-2x^2+x = 0

x(x^2-2x+1) = 0

x = 0 and x^2-2x+1 = 0

Factorize x^2-2x+1 = 0

x^2-x-x+1 = 0

x(x-1)-1(x-1) = 0

(x-1)(x-1)= 0

x = 1 twice

hence the zeros of the equation are 0, 1 and 1

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.