The 1st 3 terms of an A. P., a, a+d, and a+2d, are the same as the 1st 3 terms of a G. P.( a is not equal to 0). Show that this is only possible if r=1 and d=0

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Step-by-step explanation:

The first three terms of an A.P is equivalent to the first three terms of a G.P.

We want to show that this is only possible if r = 1 and d = 0.

If a is the initial term and d is the common difference, the A.P. will be:

Likewise, for the G.P., if a is the initial term (and it does not equal 0) and r is the common ratio, then our sequence is:

The second and third terms must be equivalent. Thus:

We can cancel the d. Multiply the first equation by -2:

We can now add this to the second equation:

Simplify:

Now, we can divide both sides by a (we can do this since a is not 0):

So:

Factor:

Thus:

The first equation tells us that:

Therefore:

Hence:

Q.E.D.

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

no idea

step-by-step explanation: