Find the area and perimeter of the polygons formed by the algebra tiles below: area: y X perimeter: 1 area: perimeter: 2​

The answer is below

Step-by-step explanation:

a)

The area of the figure = sum of the area of the individual polygons

The area of the figure = x + 1 + y + 1 + x = 2x + y  + 2

The perimeter of the figure = sum of the length of the sides = 2(1 + (x + 1 + y + 1 + x)) = 2(2x + y + 3) = 4x + 2y + 6

b)

a)

The area of the figure = sum of the area of the individual polygons

The area of the figure = y² + xy + 1 + 1 + 1 = y² + xy + 3

The perimeter of the figure = sum of the length of the sides = (y + 1) + x + y + (y + 1) + y + 1 + 1 + 1 + x + 1 = 4y + 2x + 6

step-by-step explanation:

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: