Using the method of proof by contradiction, prove that if a product of two positive real numbers is greater than 1,000,000, then at least one of the numbers is greater than 1000.

Step-by-step explanation:

To prove - Using the method of proof by contradiction, prove that if

                  a product of two positive real numbers is greater than

                  1,000,000, then at least one of the numbers is greater

                   than 1000.

Proof -

For a proof of contradiction , firstly we have to assume that the statement is not true.

Here given statement is -  A product of two positive real numbers is greater than 1,000,000.

Let if possible, there does not exist 2 +ve integer real number such that at least one of the numbers is greater than 1000.

⇒both the number are in between 0 to 1000

Let a and b are 2 +ve real numbers.

⇒ab < 1000×1000

⇒ab < 1000000

As given,

ab > 1000000

Contradiction.

Hence proved.

If a product of two positive real numbers is greater than 1,000,000, then at least one of the numbers is greater than 1000.

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6