Mathematics, 12.03.2021 19:30 anggar20
If a car has a velocity of 11 m/a west and then come to a stop in 5 s what is acceleration in m/a 2
Answers: 1
Mathematics, 21.06.2019 18:30
Haruka hiked several kilometers in the morning. she hiked only 66 kilometers in the afternoon, which was 25% less than she had hiked in the morning. how many kilometers did haruka hike in all?
Answers: 3
Mathematics, 22.06.2019 01:00
What are the solutions for the following system? -2x^2+y=-5 y=-3x^2+5
Answers: 3
Mathematics, 22.06.2019 01:00
Arrange the steps to solve this system of linear equations in the correct sequence. x + y = -2 2x β 3y = -9 tiles subtract 3x + 3y = -6 (obtained in step 1) from 2x β 3y = -9 (given) to solve for x. substitute the value of x in the first equation (x + y = -2) to get y = 1. the solution for the system of equations is (-3, 1). x = -15 the solution for the system of equations is (-15, 13). add 3x + 3y = -6 (obtained in step 1) to 2x β 3y = -9 (given), and solve for x. x = -3 substitute the value of x in the first equation (x + y = -2) to get y = 13. multiply the first equation by 3: 3(x + y) = 3(-2) 3x + 3y = -6.
Answers: 1
Mathematics, 22.06.2019 02:30
Nicolo paganini's numbers 1184 and 1210 are amicable. the proper divisors of 1184 are 1, 2, 4, 8, 16, 32, 37, 74, 148, 296, and 592. the proper divisors of 1210 are 1, 2, 5, 10, 11, 22, 55, 110, 121, 242, and 605. use the definition of amicable (friendly) numbers to show that they are indeed amicable. which of the folowing statement uses the definition of amicable numbers to show that 1184 and 1210 are indeed amicable? o a. o b. Β° c. the sum of proper divisors of 1184 is 1210 and the sum of proper divisors of 1210 is 1184 the sum of proper divisors of 1184 is greater than 1210 and the sum of proper divisors of 1210 is greater than 1184 the sum of proper divisors of 1184 is less than 1210 and the sum of proper divisors of 1210 is less than 1184
Answers: 1
If a car has a velocity of 11 m/a west and then come to a stop in 5 s what is acceleration in m/a 2...
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