Does the following scenario describe a dependent or independent sequence of events: Flipping a coin and getting a "heads" and then flipping a second coin and getting a "heads".

I hope this helps <3

Step-by-step explanation:

What's the probability of getting heads on the second toss given that the first toss was a head. (Trying to refresh my probability a bit). I've seen this analyzed like this:

HH 1/4

HT 1/4

TH 1/4

TT 1/4

So since we are given information (Head on first flip), then TT goes away and were are left with:

HH 1/3

HT 1/3

TH 1/3

So we could say that HH now has a 1/3 probability. Should we not also get rid of TH, since we know that the first flip is a head? So now we have:

HH 1/2

HT 1/2

98%

step-by-step explanation:

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).