These marbles are placed in a bag and two of them are randomly drawn.
What is the probability of drawing two blue
marbles if the first marble is placed back in
the bag before the second draw?
Give your answer as a rational number, reduced to
simplest terms.
1
Hint: Multiply the probability of the 1st Event by the
probability of the 2nd Event to get your answer.
Enter

1/4

Step-by-step explanation:

There are 2 yellow, 3 red and 5 blue for a total of 10 marbles.

The probability  of drawing a blue marble is 5/10 = 1/2

If the marble is replaced, then there are 10 marbles in the bag.

So, the probability of drawing another blue marble is 1/2

Now, multiply the two probabilities together to get the final probability.

1/2(1/2) = 1/4

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400