It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F. You are not entirely convinced. You believe that it is not 98.6∘F. You collected data using 43 healthy people and found that they had a mean body temperature of 98.21∘F with a standard deviation of
1.1∘F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6∘F.
Identify the null and alternative hypotheses?
H0 : μ =98.6
H1 : ___ ___

Identify the appropriate significance level.

d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places.

e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.

It is commonly believed that the mean body temperature of a healthy adult is

98.6

∘

F

98.6

∘

F. You are not entirely convinced. You believe that it is not

98.6

∘

F

98.6

∘

F. You collected data using 35 healthy people and found that they had a mean body temperature of

98.22

∘

F

98.22

∘

F with a standard deviaiton of

1.06

∘

F

1.06

∘

F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not

98.6

∘

F

98.6

∘

F.

Step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.