In figure, 2 triangles ABC and DBC are on the same base BC in which angle A= angle D=90°; if CA and BD meet each other at E, show that AE×CE=BE×DE. Please help
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Answer is in the photo. I can't attach it here, but I've uploaded it to a file hosting. link below! Good Luck!

cutt.ly/XzW3SUN

y=mx+b is the final answer!   : )

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c