The function f is continuous on the closed interval closed interval from pi over 3 to 5 times pi all over 3.. Selected values of f are given in the table: x pi over 3 | 2 times pi all over 3 | 4 times pi all over 3 | 5 times pi all over 3
f(x) 0.4775 | −0.2387 | −0.1194. | k

What value of k in the table would give the equation f(x) = 0 at least two solutions in the interval closed interval from pi over 3 to 5 times pi all over 3?

negative pi over 3
−0.0955
0.0955
negative 5 times pi all over 3

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