Subtract 2p^2+3q^2-2r^2+5 from 5p^2-4q^2-7r^2-6

3p²-7r²-5r²-11

Step-by-step explanation:

(5p²-4q²-72²-6)

- (2p²+3p²-2r²+5)=

3p²-7r²-5r²-11

see below

Step-by-step explanation:

Let's sim[plify step-by-step.

5p²−4q²−7r²-6−(2p²+3q²−2r²+5)

Distribute the Negative Sign:

=5p²−4q²−7r²−6+−1(2p²+3q²−2r²+5)

=5p²+−4q²+−7r²+−6+−1(2p²)+−1(3q²)+−1(−2r ²)+(−1)(5)

=5p²+−4q²+−7r²+−6+−2p²+−3q²+2r²+−5

Combine Like Terms:

=5p²+−4q²+−7r²+−6+−2p²+−3q²+2r²+−5

=(5p²+−2²)+(−4q²+−3q²)+(−7r²+2r²)+(−6+−5)

=3p²+−7q²+−5r²+−11

=3p²−7q²−5r²−11

7 weeks

step-by-step explanation:

convert each fraction to the least common multiple of 20, so 3/4 = 15/20 & 1/10 = 2/20, then divide 15 by 2 and you get a little over 7, so the food will last 7 weeks.

the answer is 0.071

good luck! : d